- A. Grape
- B. Cauliflower
- C. Garlic correct
- D. Chilli
GATE XE 2025 Food Technology question paper
Every Food Technology question from the GATE Engineering Sciences (XE) paper sat in 2025, exactly as it was set — with the options and the answer key. The full paper's section-by-section pattern is below.
- Food Technology questions
- 22
- Food Technology marks
- 35
- Full paper
- 261 marks
- Duration
- 180 minutes
What the 2025 paper contained
Counted from the paper itself, not from a notification — the row highlighted below is the section this page reproduces.
| Section | Questions | Marks | Question types |
|---|---|---|---|
| General Aptitude | 7 | 11 | 7 MCQ |
| Engineering Mathematics | 10 | 14 | 6 MCQ, 1 MSQ, 3 NAT |
| Fluid Mechanics | 20 | 33 | 12 MCQ, 8 NAT |
| Materials Science | 21 | 33 | 7 MCQ, 3 MSQ, 11 NAT |
| Solid Mechanics | 21 | 34 | 9 MCQ, 3 MSQ, 9 NAT |
| Thermodynamics | 20 | 33 | 5 MCQ, 2 MSQ, 13 NAT |
| Polymer Science and Engineering | 21 | 33 | 9 MCQ, 7 MSQ, 5 NAT |
| Food Technology | 22 | 35 | 11 MCQ, 5 MSQ, 6 NAT |
| Atmospheric and Ocean Sciences | 22 | 35 | 12 MCQ, 2 MSQ, 8 NAT |
Sit it timed
Attempt the 2025 paper properly
Reading the answer key is not the same as sitting the paper. Take it timed and scored, with the worked solution behind every question and your rank against everyone else who has attempted it.
Food Technology questions, 2025 — with answer key
22 questions, numbered as they were in the paper. The correct option is marked on each.
cheese?
- A. Rhizopus oryzae
- B. Penicillium roqueforti correct
- C. Aspergillus niger
- D. Penicillium camemberti
- A. Lactobacillus
- B. Staphylococcus
- C. Mycoplasma correct
- D. Escherichia
- A. beta -Carotene
- B. beta -Cryptoxanthin
- C. Lycopene correct
- D. alpha -Carotene
spice/herb powders.
- A. Acid-insoluble ash content correct
- B. Pesticide residue levels
- C. Volatile oil content
- D. Mycotoxin levels
quality of rice bran oil deteriorates. Identify the suitable CAUSE and EFFECT for
the deterioration in oil quality.
- A. Lipase activity; increase in FFA correct
- B. Oil hydrolysis; decrease in FFA
- C. Lipase activity; decrease in FFA
- D. Bran stabilization; decrease in lipase activity
fats from existing ones?
- A. Transesterification correct
- B. Degumming
- C. Hydrogenation correct
- D. Winterization
respectively. The porosity of the grains is ____. (rounded off to 2 decimal places)
Correct: 0.4 to 0.44
moisture content (dry basis). The amount of dried potato slices obtained (in kg) is
_______. (Answer in integer)
Correct: 21
MAP conditions.
- A. O2 = 0; CO2 = 50; N2 = 50 correct
- B. O2 = 50; CO2 = 0; N2 = 50
- C. O2 = 0; CO2 = 0; N2 = 100
- D. O2 = 50; CO2 = 50; N2 = 0
gel?
Assume: PN: Native protein; PD: Denatured protein;
PA: Aggregated protein; PG: Protein gel
→: forward reaction; : reversible reaction; ∆: heating; ∇: cooling
- A. PN ∆↔ PD ∇↔ PA ∇↔ PG
- B. PN ∆↔ PD ∆→ PA ∆→ PG correct
- C. PN ∆↔ PD ∇→ PG
- D. PN ∆↔ PA ∆→ PG
of Ball process time (B)?
Assume: tp = processor’s process time; tc = come-up time
- A. B = tp + 0.42 tc correct
- B. B = tp + 0.30 tc
- C. B = tp + 0.50 tc
- D. B = tp + 0.25 tc
fruits?
- A. PET/LDPE
- B. PS/LDPE
- C. BOPP/LDPE correct
- D. Nylon/LDPE
- A. Slaughtering and bleeding → scalding → defeathering → eviscerating → chilling correct
- B. Slaughtering and bleeding → defeathering → scalding → eviscerating → chilling
- C. Slaughtering and bleeding →eviscerating → defeathering → scalding →chilling
- D. Slaughtering and bleeding → defeathering → eviscerating → scalding → chilling
irradiated (7.5 kGy) whole chicken?
- A. Nutritional quality of the product deteriorates after irradiation.
- B. Spores of C. botulinum can survive in the irradiated product. correct
- C. ‘Radura’ symbol does not ensure safety of the irradiated product for consumption. correct
- D. Energy needed for the irradiation process is much higher than that required for freezing of the product.
in Column II.
Column I
Column II
P
Idli
1
Baking
Q
Parboiled rice
2
Fermentation
R
Soda beverage
3
Gelatinization
S
Cookies
4
Carbonation
- A. P-2;Q-3;R-4;S-1 correct
- B. P-3;Q-2;R-4;S-1
- C. P-2;Q-4;R-1;S-3
- D. P-2;Q-3;R-1;S-4
potatoes?
- A. Citric acid correct
- B. EDTA correct
- C. Mannitol
- D. Ascorbic acid correct
Column I
Column II
P
beta -Glucanase
1
Fruit juice clarification
Q
alpha - and beta -Amylases
2
Bread making
R
Pectinase
3
Meat tenderization
S
Papain
4
Brewing
- A. P-3;Q-1;R-2;S-4
- B. P-4;Q-2;R-1;S-3 correct
- C. P-2;Q-4;R-1;S-3 correct
- D. P-1;Q-2;R-3;S-4
99.9999% inactivation. For a 12D inactivation of the said microorganism at
143 °C, the F value (in min) is _____. (rounded off to 3 decimal places)
Correct: 0.046 to 0.05
constant: 4.48, 1.88 and 1.0 kJ/ (kg °C), respectively. Assuming, the heat energy
required to convert 1 kg of water to water vapour at 0 °C is 2000 kJ, the enthalpy
(in kJ/ kg dry air) of atmospheric air containing 0.05 kg water vapour per kg dry
air at 50 °C is ____.(rounded off to 1 decimal place)
Correct: 152 to 156
10 kg/min with 6% total solids (by weight) is increased to 20% total solids (by
weight). The membrane tube has 10 cm inside diameter and the pressure difference
across the membrane is 2000 kPa. If the permeability constant of the membrane is
5 × 10-5 kg water/ (m2 kPa s), the length of membrane tube (in m) is______.
(rounded off to 2 decimal places)
Correct: 3.65 to 3.75
opening of 4.75 mm; whereas, 80% of the ground product passes through 0.5 mm
opening. If the power required to grind 2 tonnes/h of the feed material is
3.8 kW, the work index of the material is _______. (rounded off to 2 decimal
places)
Correct: 6.25 to 6.32
Worked solutions are not printed here — every one of these questions carries a full explanation inside the test itself, which is where it is actually useful: after you have committed to an answer. Sit the 2025 paper.
Other GATE XE papers
Or see every GATE XE mock test on the site — full papers, sectional tests and the exam pattern.